The amount of work done in forming a soap film of size $10 …

Physics Surface Tension Surface Energy Single Correct MCQ

Published on: September 12, 2026

The amount of work done in forming a soap film of size $10 \mathrm{cm} \times 10 \mathrm{cm}$ is (Surface tension $\mathbf{T} = 3 \times 10^{-2} \mathrm{N/m}$

$6 \times 10^{-4} \mathrm{J}$

$3 \times 10^{-4} \mathrm{J}$

$6 \times 10^{-3}$

$3 \times 10^{-4} \mathrm{J}$

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The correct answer is:

$E = T \times \Delta A = 3 \times 10^{-2} \times 2(100 \times 10^{-4}) = 6 \times 10^{-4} \mathrm{J}$

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